Solve 6{18-[8(c+1)-2(c+1)]}=-12c

$$6 \{ 18 - [ 8 ( c + 1 ) - 2 ( c + 1 ) ] \} = - 12 c$$

Solve for c

$$c=3$$

Steps for Solving Linear Equation

Use the distributive property to multiply 8 by c+1.

$$6\left(18-\left(8c+8-2\left(c+1\right)\right)\right)=-12c$$

Use the distributive property to multiply -2 by c+1.

$$6\left(18-\left(8c+8-2c-2\right)\right)=-12c$$

Combine 8c and -2c to get 6c.

$$6\left(18-\left(6c+8-2\right)\right)=-12c$$

Subtract 2 from 8 to get 6.

$$6\left(18-\left(6c+6\right)\right)=-12c$$

To find the opposite of 6c+6, find the opposite of each term.

$$6\left(18-6c-6\right)=-12c$$

Subtract 6 from 18 to get 12.

$$6\left(12-6c\right)=-12c$$

Use the distributive property to multiply 6 by 12-6c.

$$72-36c=-12c$$

Add 12c to both sides.

$$72-36c+12c=0$$

Combine -36c and 12c to get -24c.

$$72-24c=0$$

Subtract 72 from both sides. Anything subtracted from zero gives its negation.

$$-24c=-72$$

Divide both sides by -24.

$$c=\frac{-72}{-24}$$

Divide -72 by -24 to get 3.

$$c=3$$