Solve 6^3-6*6^2+9*6-2=0

$$6 ^ { 3 } - 6 \cdot 6 ^ { 2 } + 9 \cdot 6 - 2 = 0$$

Verify

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$6^{3}-6^{3}+9\times 6-2=0$$

Calculate 6 to the power of 3 and get 216.

$$216-6^{3}+9\times 6-2=0$$

Calculate 6 to the power of 3 and get 216.

$$216-216+9\times 6-2=0$$

Subtract 216 from 216 to get 0.

$$0+9\times 6-2=0$$

Multiply 9 and 6 to get 54.

$$0+54-2=0$$

Add 0 and 54 to get 54.

$$54-2=0$$

Subtract 2 from 54 to get 52.

$$52=0$$

Compare 52 and 0.

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