Solve 6^2div3^2*(1-2^3+3)

$$6 ^ { 2 } \div 3 ^ { 2 } \times ( 1 - 2 ^ { 3 } + 3 )$$

Evaluate

$$-16$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$\frac{36}{3^{2}}\left(1-2^{3}+3\right)$$

Calculate 3 to the power of 2 and get 9.

$$\frac{36}{9}\left(1-2^{3}+3\right)$$

Divide 36 by 9 to get 4.

$$4\left(1-2^{3}+3\right)$$

Calculate 2 to the power of 3 and get 8.

$$4\left(1-8+3\right)$$

Subtract 8 from 1 to get -7.

$$4\left(-7+3\right)$$

Add -7 and 3 to get -4.

$$4\left(-4\right)$$

Multiply 4 and -4 to get -16.

$$-16$$

Factor

$$-16$$