Solve 6^2+[sqrt{36}+(sqrt{225}-12^circ)]

$$6 ^ { 2 } + [ \sqrt { 36 } + ( \sqrt { 225 } - 12 ^ { \circ } ) ]$$

Evaluate

$$45$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$36+\sqrt{36}+\sqrt{225}-12$$

Calculate the square root of 36 and get 6.

$$36+6+\sqrt{225}-12$$

Add 36 and 6 to get 42.

$$42+\sqrt{225}-12$$

Calculate the square root of 225 and get 15.

$$42+15-12$$

Add 42 and 15 to get 57.

$$57-12$$

Subtract 12 from 57 to get 45.

$$45$$

Factor

$$3^{2}\times 5$$