Solve for b
b=\frac{2-3c}{5}
Solve for c
c=\frac{2-5b}{3}
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15b+9c=6
Swap sides so that all variable terms are on the left hand side.
15b=6-9c
Subtract 9c from both sides.
\frac{15b}{15}=\frac{6-9c}{15}
Divide both sides by 15.
b=\frac{6-9c}{15}
Dividing by 15 undoes the multiplication by 15.
b=\frac{2-3c}{5}
Divide 6-9c by 15.
15b+9c=6
Swap sides so that all variable terms are on the left hand side.
9c=6-15b
Subtract 15b from both sides.
\frac{9c}{9}=\frac{6-15b}{9}
Divide both sides by 9.
c=\frac{6-15b}{9}
Dividing by 9 undoes the multiplication by 9.
c=\frac{2-5b}{3}
Divide 6-15b by 9.
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