Solve 6=1/3x-1/2

$$6 = \frac { 1 } { 3 } x - \frac { 1 } { 2 }$$

Solve for x

$$x = \frac{39}{2} = 19\frac{1}{2} = 19.5$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}x-\frac{1}{2}=6$$

Add \frac{1}{2} to both sides.

$$\frac{1}{3}x=6+\frac{1}{2}$$

Convert 6 to fraction \frac{12}{2}.

$$\frac{1}{3}x=\frac{12}{2}+\frac{1}{2}$$

Since \frac{12}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{1}{3}x=\frac{12+1}{2}$$

Add 12 and 1 to get 13.

$$\frac{1}{3}x=\frac{13}{2}$$

Multiply both sides by 3, the reciprocal of \frac{1}{3}.

$$x=\frac{13}{2}\times 3$$

Express \frac{13}{2}\times 3 as a single fraction.

$$x=\frac{13\times 3}{2}$$

Multiply 13 and 3 to get 39.

$$x=\frac{39}{2}$$