Solve 6+6^2div2*(3^3-26)^19+106*10^3

$$6 + 6 ^ { 2 } \div 2 \times ( 3 ^ { 3 } - 26 ) ^ { 19 } + 106 \times 10 ^ { 3 }$$

Evaluate

$$106024$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$6+\frac{36}{2}\left(3^{3}-26\right)^{19}+106\times 10^{3}$$

Divide 36 by 2 to get 18.

$$6+18\left(3^{3}-26\right)^{19}+106\times 10^{3}$$

Calculate 3 to the power of 3 and get 27.

$$6+18\left(27-26\right)^{19}+106\times 10^{3}$$

Subtract 26 from 27 to get 1.

$$6+18\times 1^{19}+106\times 10^{3}$$

Calculate 1 to the power of 19 and get 1.

$$6+18\times 1+106\times 10^{3}$$

Multiply 18 and 1 to get 18.

$$6+18+106\times 10^{3}$$

Add 6 and 18 to get 24.

$$24+106\times 10^{3}$$

Calculate 10 to the power of 3 and get 1000.

$$24+106\times 1000$$

Multiply 106 and 1000 to get 106000.

$$24+106000$$

Add 24 and 106000 to get 106024.

$$106024$$

Factor

$$2^{3}\times 29\times 457$$