Solve 6+6^2div2*(3^3-26)^19+1.06*10^3

$$6 + 6 ^ { 2 } \div 2 \times ( 3 ^ { 3 } - 26 ) ^ { 19 } + 1.06 \times 10 ^ { 3 }$$

Evaluate

$$1084$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$6+\frac{36}{2}\left(3^{3}-26\right)^{19}+1.06\times 10^{3}$$

Divide 36 by 2 to get 18.

$$6+18\left(3^{3}-26\right)^{19}+1.06\times 10^{3}$$

Calculate 3 to the power of 3 and get 27.

$$6+18\left(27-26\right)^{19}+1.06\times 10^{3}$$

Subtract 26 from 27 to get 1.

$$6+18\times 1^{19}+1.06\times 10^{3}$$

Calculate 1 to the power of 19 and get 1.

$$6+18\times 1+1.06\times 10^{3}$$

Multiply 18 and 1 to get 18.

$$6+18+1.06\times 10^{3}$$

Add 6 and 18 to get 24.

$$24+1.06\times 10^{3}$$

Calculate 10 to the power of 3 and get 1000.

$$24+1.06\times 1000$$

Multiply 1.06 and 1000 to get 1060.

$$24+1060$$

Add 24 and 1060 to get 1084.

$$1084$$

Factor

$$271\times 2^{2}$$