Solve 6+6+6+(6+2)+9+(a+2)

$$6 + 6 + 6 + ( 6 + 2 ) + 9 + ( a + 2 )$$

Evaluate

$$a+37$$

Solution Steps

Add 6 and 6 to get 12.

$$12+6+6+2+9+a+2$$

Add 12 and 6 to get 18.

$$18+6+2+9+a+2$$

Add 18 and 6 to get 24.

$$24+2+9+a+2$$

Add 24 and 2 to get 26.

$$26+9+a+2$$

Add 26 and 9 to get 35.

$$35+a+2$$

Add 35 and 2 to get 37.

$$37+a$$

Differentiate w.r.t. a

$$1$$

Steps Using Derivative Rule for Sum

Add 6 and 6 to get 12.

$$\frac{\mathrm{d}}{\mathrm{d}a}(12+6+6+2+9+a+2)$$

Add 12 and 6 to get 18.

$$\frac{\mathrm{d}}{\mathrm{d}a}(18+6+2+9+a+2)$$

Add 18 and 6 to get 24.

$$\frac{\mathrm{d}}{\mathrm{d}a}(24+2+9+a+2)$$

Add 24 and 2 to get 26.

$$\frac{\mathrm{d}}{\mathrm{d}a}(26+9+a+2)$$

Add 26 and 9 to get 35.

$$\frac{\mathrm{d}}{\mathrm{d}a}(35+a+2)$$

Add 35 and 2 to get 37.

$$\frac{\mathrm{d}}{\mathrm{d}a}(37+a)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$a^{1-1}$$

Subtract 1 from 1.

$$a^{0}$$

For any term t except 0, t^{0}=1.

$$1$$