Solve 6+4xgeq2(19x+8)

$$6 + 4 x \geq 2 ( 19 x + 8 )$$

Solve for x

$$x\leq -\frac{5}{17}$$

Solution Steps

Use the distributive property to multiply 2 by 19x+8.

$$6+4x\geq 38x+16$$

Subtract 38x from both sides.

$$6+4x-38x\geq 16$$

Combine 4x and -38x to get -34x.

$$6-34x\geq 16$$

Subtract 6 from both sides.

$$-34x\geq 16-6$$

Subtract 6 from 16 to get 10.

$$-34x\geq 10$$

Divide both sides by -34. Since -34 is negative, the inequality direction is changed.

$$x\leq \frac{10}{-34}$$

Reduce the fraction \frac{10}{-34} to lowest terms by extracting and canceling out 2.

$$x\leq -\frac{5}{17}$$