Solve 6+2{3-[5+(4-6)-(7-3)+2]-4}=

$$6 + 2 \{ 3 - [ 5 + ( 4 - 6 ) - ( 7 - 3 ) + 2 ] - 4 \} =$$

Evaluate

$$2$$

Solution Steps

Add 5 and 4 to get 9.

$$6+2\left(3-\left(9-6-\left(7-3\right)+2\right)-4\right)$$

Subtract 6 from 9 to get 3.

$$6+2\left(3-\left(3-\left(7-3\right)+2\right)-4\right)$$

Subtract 3 from 7 to get 4.

$$6+2\left(3-\left(3-4+2\right)-4\right)$$

Subtract 4 from 3 to get -1.

$$6+2\left(3-\left(-1+2\right)-4\right)$$

Add -1 and 2 to get 1.

$$6+2\left(3-1-4\right)$$

Subtract 1 from 3 to get 2.

$$6+2\left(2-4\right)$$

Subtract 4 from 2 to get -2.

$$6+2\left(-2\right)$$

Multiply 2 and -2 to get -4.

$$6-4$$

Subtract 4 from 6 to get 2.

$$2$$

Factor

$$2$$