Solve 6+0<(1/8-1/10)

$$6 + 0 < ( \frac { 1 } { 8 } - \frac { 1 } { 10 } )$$

Verify

Solution Steps

Add 6 and 0 to get 6.

$$6<\frac{1}{8}-\frac{1}{10}$$

Least common multiple of 8 and 10 is 40. Convert \frac{1}{8} and \frac{1}{10} to fractions with denominator 40.

$$6<\frac{5}{40}-\frac{4}{40}$$

Since \frac{5}{40} and \frac{4}{40} have the same denominator, subtract them by subtracting their numerators.

$$6<\frac{5-4}{40}$$

Subtract 4 from 5 to get 1.

$$6<\frac{1}{40}$$

Convert 6 to fraction \frac{240}{40}.

$$\frac{240}{40}<\frac{1}{40}$$

Compare \frac{240}{40} and \frac{1}{40}.

$$\text{false}$$