Solve 6+4/3*21/28+31/2*73/5=

$$6 + \frac { 4 } { 3 } \cdot \frac { 21 } { 28 } + 3 \frac { 1 } { 2 } \cdot 7 \frac { 3 } { 5 } =$$

Evaluate

$$\frac{168}{5}=33.6$$

Solution Steps

Reduce the fraction \frac{21}{28} to lowest terms by extracting and canceling out 7.

$$6+\frac{4}{3}\times \frac{3}{4}+\frac{3\times 2+1}{2}\times \frac{7\times 5+3}{5}$$

Cancel out \frac{4}{3} and its reciprocal \frac{3}{4}.

$$6+1+\frac{3\times 2+1}{2}\times \frac{7\times 5+3}{5}$$

Add 6 and 1 to get 7.

$$7+\frac{3\times 2+1}{2}\times \frac{7\times 5+3}{5}$$

Multiply 3 and 2 to get 6.

$$7+\frac{6+1}{2}\times \frac{7\times 5+3}{5}$$

Add 6 and 1 to get 7.

$$7+\frac{7}{2}\times \frac{7\times 5+3}{5}$$

Multiply 7 and 5 to get 35.

$$7+\frac{7}{2}\times \frac{35+3}{5}$$

Add 35 and 3 to get 38.

$$7+\frac{7}{2}\times \frac{38}{5}$$

Multiply \frac{7}{2} times \frac{38}{5} by multiplying numerator times numerator and denominator times denominator.

$$7+\frac{7\times 38}{2\times 5}$$

Do the multiplications in the fraction \frac{7\times 38}{2\times 5}.

$$7+\frac{266}{10}$$

Reduce the fraction \frac{266}{10} to lowest terms by extracting and canceling out 2.

$$7+\frac{133}{5}$$

Convert 7 to fraction \frac{35}{5}.

$$\frac{35}{5}+\frac{133}{5}$$

Since \frac{35}{5} and \frac{133}{5} have the same denominator, add them by adding their numerators.

$$\frac{35+133}{5}$$

Add 35 and 133 to get 168.

$$\frac{168}{5}$$

Factor

$$\frac{2 ^ {3} \cdot 3 \cdot 7}{5} = 33\frac{3}{5} = 33.6$$