Solve for x
x=\frac{5y}{6}-\frac{4}{3}
Solve for y
y=\frac{6x+8}{5}
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6x+18=5y+10
Swap sides so that all variable terms are on the left hand side.
6x=5y+10-18
Subtract 18 from both sides.
6x=5y-8
Subtract 18 from 10 to get -8.
\frac{6x}{6}=\frac{5y-8}{6}
Divide both sides by 6.
x=\frac{5y-8}{6}
Dividing by 6 undoes the multiplication by 6.
x=\frac{5y}{6}-\frac{4}{3}
Divide 5y-8 by 6.
5y=6x+18-10
Subtract 10 from both sides.
5y=6x+8
Subtract 10 from 18 to get 8.
\frac{5y}{5}=\frac{6x+8}{5}
Divide both sides by 5.
y=\frac{6x+8}{5}
Dividing by 5 undoes the multiplication by 5.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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