Solve for x
x=\frac{9y-43}{5}
Solve for y
y=\frac{5x+43}{9}
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5x=-43+9y
Add 9y to both sides.
5x=9y-43
The equation is in standard form.
\frac{5x}{5}=\frac{9y-43}{5}
Divide both sides by 5.
x=\frac{9y-43}{5}
Dividing by 5 undoes the multiplication by 5.
-9y=-43-5x
Subtract 5x from both sides.
-9y=-5x-43
The equation is in standard form.
\frac{-9y}{-9}=\frac{-5x-43}{-9}
Divide both sides by -9.
y=\frac{-5x-43}{-9}
Dividing by -9 undoes the multiplication by -9.
y=\frac{5x+43}{9}
Divide -43-5x by -9.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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