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5x+1=8y
Add 8y to both sides. Anything plus zero gives itself.
5x=8y-1
Subtract 1 from both sides.
\frac{5x}{5}=\frac{8y-1}{5}
Divide both sides by 5.
x=\frac{8y-1}{5}
Dividing by 5 undoes the multiplication by 5.
-8y+1=-5x
Subtract 5x from both sides. Anything subtracted from zero gives its negation.
-8y=-5x-1
Subtract 1 from both sides.
\frac{-8y}{-8}=\frac{-5x-1}{-8}
Divide both sides by -8.
y=\frac{-5x-1}{-8}
Dividing by -8 undoes the multiplication by -8.
y=\frac{5x+1}{8}
Divide -5x-1 by -8.