Solve 5x-4-5/3x-8/3=0

$$5x-4- \frac{ 5 }{ 3 } x- \frac{ 8 }{ 3 } =0$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Combine 5x and -\frac{5}{3}x to get \frac{10}{3}x.

$$\frac{10}{3}x-4-\frac{8}{3}=0$$

Convert -4 to fraction -\frac{12}{3}.

$$\frac{10}{3}x-\frac{12}{3}-\frac{8}{3}=0$$

Since -\frac{12}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{10}{3}x+\frac{-12-8}{3}=0$$

Subtract 8 from -12 to get -20.

$$\frac{10}{3}x-\frac{20}{3}=0$$

Add \frac{20}{3} to both sides. Anything plus zero gives itself.

$$\frac{10}{3}x=\frac{20}{3}$$

Multiply both sides by \frac{3}{10}, the reciprocal of \frac{10}{3}.

$$x=\frac{20}{3}\times \frac{3}{10}$$

Multiply \frac{20}{3} times \frac{3}{10} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{20\times 3}{3\times 10}$$

Cancel out 3 in both numerator and denominator.

$$x=\frac{20}{10}$$

Divide 20 by 10 to get 2.

$$x=2$$