Solve 5x-(20-3-x)*2geq60

$$5x-(20-3-x) \times 2 \geq 60$$

Solve for x

$$x\geq \frac{94}{7}$$

Solution Steps

Subtract 3 from 20 to get 17.

$$5x-\left(17-x\right)\times 2\geq 60$$

Use the distributive property to multiply 17-x by 2.

$$5x-\left(34-2x\right)\geq 60$$

To find the opposite of 34-2x, find the opposite of each term.

$$5x-34-\left(-2x\right)\geq 60$$

The opposite of -2x is 2x.

$$5x-34+2x\geq 60$$

Combine 5x and 2x to get 7x.

$$7x-34\geq 60$$

Add 34 to both sides.

$$7x\geq 60+34$$

Add 60 and 34 to get 94.

$$7x\geq 94$$

Divide both sides by 7. Since 7 is positive, the inequality direction remains the same.

$$x\geq \frac{94}{7}$$