Solve for x
x\leq \frac{7}{3}
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5x+8-8x\geq 1
Subtract 8x from both sides.
-3x+8\geq 1
Combine 5x and -8x to get -3x.
-3x\geq 1-8
Subtract 8 from both sides.
-3x\geq -7
Subtract 8 from 1 to get -7.
x\leq \frac{-7}{-3}
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
x\leq \frac{7}{3}
Fraction \frac{-7}{-3} can be simplified to \frac{7}{3} by removing the negative sign from both the numerator and the denominator.
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