Solve for x
x>\frac{40}{3}
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3x+60>100
Combine 5x and -2x to get 3x.
3x>100-60
Subtract 60 from both sides.
3x>40
Subtract 60 from 100 to get 40.
x>\frac{40}{3}
Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.
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