Solve 5x+14.5y+52.27z=-7

$$5x+14.5y+52.27z=-7$$

Solve for x

$$x=-\frac{29y}{10}-\frac{5227z}{500}-1.4$$

Steps for Solving Linear Equation

Subtract 14.5y from both sides.

$$5x+52.27z=-7-14.5y$$

Subtract 52.27z from both sides.

$$5x=-7-14.5y-52.27z$$

The equation is in standard form.

$$5x=-\frac{29y}{2}-\frac{5227z}{100}-7$$

Divide both sides by 5.

$$\frac{5x}{5}=\frac{-\frac{29y}{2}-\frac{5227z}{100}-7}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$x=\frac{-\frac{29y}{2}-\frac{5227z}{100}-7}{5}$$

Divide -7-\frac{29y}{2}-\frac{5227z}{100} by 5.

$$x=-\frac{29y}{10}-\frac{5227z}{500}-\frac{7}{5}$$

Solve for y

$$y=-\frac{10x}{29}-\frac{5227z}{1450}-\frac{14}{29}$$

Steps for Solving Linear Equation

Subtract 5x from both sides.

$$14.5y+52.27z=-7-5x$$

Subtract 52.27z from both sides.

$$14.5y=-7-5x-52.27z$$

The equation is in standard form.

$$14.5y=-\frac{5227z}{100}-5x-7$$

Divide both sides of the equation by 14.5, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{14.5y}{14.5}=\frac{-\frac{5227z}{100}-5x-7}{14.5}$$

Dividing by 14.5 undoes the multiplication by 14.5.

$$y=\frac{-\frac{5227z}{100}-5x-7}{14.5}$$

Divide -7-5x-\frac{5227z}{100} by 14.5 by multiplying -7-5x-\frac{5227z}{100} by the reciprocal of 14.5.

$$y=-\frac{10x}{29}-\frac{5227z}{1450}-\frac{14}{29}$$