Solve 5x+(y^22)=32

$$5x+( { y }^{ 2 } 2)=32$$

Solve for x

$$x=\frac{32-2y^{2}}{5}$$

Steps for Solving Linear Equation

Subtract y^{2}\times 2 from both sides.

$$5x=32-y^{2}\times 2$$

Multiply -1 and 2 to get -2.

$$5x=32-2y^{2}$$

Divide both sides by 5.

$$\frac{5x}{5}=\frac{32-2y^{2}}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$x=\frac{32-2y^{2}}{5}$$

Solve for y (complex solution)

$$y=-\frac{\sqrt{64-10x}}{2}$$

$$y=\frac{\sqrt{64-10x}}{2}$$

Solve for y

$$y=\frac{\sqrt{64-10x}}{2}$$

$$y=-\frac{\sqrt{64-10x}}{2}\text{, }x\leq \frac{32}{5}$$