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5x^{2}=90
Multiply x and x to get x^{2}.
x^{2}=\frac{90}{5}
Divide both sides by 5.
x^{2}=18
Divide 90 by 5 to get 18.
x=3\sqrt{2} x=-3\sqrt{2}
Take the square root of both sides of the equation.
5x^{2}=90
Multiply x and x to get x^{2}.
5x^{2}-90=0
Subtract 90 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 5\left(-90\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -90 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\left(-90\right)}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\left(-90\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{1800}}{2\times 5}
Multiply -20 times -90.
x=\frac{0±30\sqrt{2}}{2\times 5}
Take the square root of 1800.
x=\frac{0±30\sqrt{2}}{10}
Multiply 2 times 5.
x=3\sqrt{2}
Now solve the equation x=\frac{0±30\sqrt{2}}{10} when ± is plus.
x=-3\sqrt{2}
Now solve the equation x=\frac{0±30\sqrt{2}}{10} when ± is minus.
x=3\sqrt{2} x=-3\sqrt{2}
The equation is now solved.