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5xx=6\times 52
Multiply both sides by 52.
5x^{2}=6\times 52
Multiply x and x to get x^{2}.
5x^{2}=312
Multiply 6 and 52 to get 312.
x^{2}=\frac{312}{5}
Divide both sides by 5.
x=\frac{2\sqrt{390}}{5} x=-\frac{2\sqrt{390}}{5}
Take the square root of both sides of the equation.
5xx=6\times 52
Multiply both sides by 52.
5x^{2}=6\times 52
Multiply x and x to get x^{2}.
5x^{2}=312
Multiply 6 and 52 to get 312.
5x^{2}-312=0
Subtract 312 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 5\left(-312\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -312 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\left(-312\right)}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\left(-312\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{6240}}{2\times 5}
Multiply -20 times -312.
x=\frac{0±4\sqrt{390}}{2\times 5}
Take the square root of 6240.
x=\frac{0±4\sqrt{390}}{10}
Multiply 2 times 5.
x=\frac{2\sqrt{390}}{5}
Now solve the equation x=\frac{0±4\sqrt{390}}{10} when ± is plus.
x=-\frac{2\sqrt{390}}{5}
Now solve the equation x=\frac{0±4\sqrt{390}}{10} when ± is minus.
x=\frac{2\sqrt{390}}{5} x=-\frac{2\sqrt{390}}{5}
The equation is now solved.