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5x^{2}\times 5=10
Multiply x and x to get x^{2}.
25x^{2}=10
Multiply 5 and 5 to get 25.
x^{2}=\frac{10}{25}
Divide both sides by 25.
x^{2}=\frac{2}{5}
Reduce the fraction \frac{10}{25} to lowest terms by extracting and canceling out 5.
x=\frac{\sqrt{10}}{5} x=-\frac{\sqrt{10}}{5}
Take the square root of both sides of the equation.
5x^{2}\times 5=10
Multiply x and x to get x^{2}.
25x^{2}=10
Multiply 5 and 5 to get 25.
25x^{2}-10=0
Subtract 10 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 25\left(-10\right)}}{2\times 25}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 25 for a, 0 for b, and -10 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 25\left(-10\right)}}{2\times 25}
Square 0.
x=\frac{0±\sqrt{-100\left(-10\right)}}{2\times 25}
Multiply -4 times 25.
x=\frac{0±\sqrt{1000}}{2\times 25}
Multiply -100 times -10.
x=\frac{0±10\sqrt{10}}{2\times 25}
Take the square root of 1000.
x=\frac{0±10\sqrt{10}}{50}
Multiply 2 times 25.
x=\frac{\sqrt{10}}{5}
Now solve the equation x=\frac{0±10\sqrt{10}}{50} when ± is plus.
x=-\frac{\sqrt{10}}{5}
Now solve the equation x=\frac{0±10\sqrt{10}}{50} when ± is minus.
x=\frac{\sqrt{10}}{5} x=-\frac{\sqrt{10}}{5}
The equation is now solved.