Solve 590-3left(-10+2Q+Qright)=20+6Q

$$590-3 \left( -10+2Q+Q \right) = 20+6Q$$

Solve for Q

$$Q=40$$

Steps for Solving Linear Equation

Combine 2Q and Q to get 3Q.

$$590-3\left(-10+3Q\right)=20+6Q$$

Use the distributive property to multiply -3 by -10+3Q.

$$590+30-9Q=20+6Q$$

Add 590 and 30 to get 620.

$$620-9Q=20+6Q$$

Subtract 6Q from both sides.

$$620-9Q-6Q=20$$

Combine -9Q and -6Q to get -15Q.

$$620-15Q=20$$

Subtract 620 from both sides.

$$-15Q=20-620$$

Subtract 620 from 20 to get -600.

$$-15Q=-600$$

Divide both sides by -15.

$$Q=\frac{-600}{-15}$$

Divide -600 by -15 to get 40.

$$Q=40$$