Solve 57.2+0.6x<42

$$57.2 + 0.6 x < 42$$

Solve for x

$$x<-\frac{76}{3}$$

Solution Steps

Subtract 57.2 from both sides.

$$0.6x<42-57.2$$

Subtract 57.2 from 42 to get -15.2.

$$0.6x<-15.2$$

Divide both sides by 0.6. Since 0.6 is positive, the inequality direction remains the same.

$$x<\frac{-15.2}{0.6}$$

Expand \frac{-15.2}{0.6} by multiplying both numerator and the denominator by 10.

$$x<\frac{-152}{6}$$

Reduce the fraction \frac{-152}{6} to lowest terms by extracting and canceling out 2.

$$x<-\frac{76}{3}$$