Solve 57+(2/10*3/8)div58

$$57 + ( \frac { 2 } { 10 } \times \frac { 3 } { 8 } ) \div 58$$

Evaluate

$$\frac{132243}{2320}\approx 57.001293103$$

Solution Steps

Reduce the fraction \frac{2}{10} to lowest terms by extracting and canceling out 2.

$$57+\frac{\frac{1}{5}\times \frac{3}{8}}{58}$$

Multiply \frac{1}{5} times \frac{3}{8} by multiplying numerator times numerator and denominator times denominator.

$$57+\frac{\frac{1\times 3}{5\times 8}}{58}$$

Do the multiplications in the fraction \frac{1\times 3}{5\times 8}.

$$57+\frac{\frac{3}{40}}{58}$$

Express \frac{\frac{3}{40}}{58} as a single fraction.

$$57+\frac{3}{40\times 58}$$

Multiply 40 and 58 to get 2320.

$$57+\frac{3}{2320}$$

Convert 57 to fraction \frac{132240}{2320}.

$$\frac{132240}{2320}+\frac{3}{2320}$$

Since \frac{132240}{2320} and \frac{3}{2320} have the same denominator, add them by adding their numerators.

$$\frac{132240+3}{2320}$$

Add 132240 and 3 to get 132243.

$$\frac{132243}{2320}$$

Factor

$$\frac{3 \cdot 17 \cdot 2593}{2 ^ {4} \cdot 5 \cdot 29} = 57\frac{3}{2320} = 57.001293103448276$$