Solve 560+[(102)4]-(7div(6)4)=

$$560 + [ ( 102 ) 4 ] - ( 7 \div ( 6 ) 4 ) =$$

Evaluate

$$\frac{2890}{3}\approx 963.333333333$$

Solution Steps

Multiply 102 and 4 to get 408.

$$560+408-\frac{7}{6}\times 4$$

Add 560 and 408 to get 968.

$$968-\frac{7}{6}\times 4$$

Express \frac{7}{6}\times 4 as a single fraction.

$$968-\frac{7\times 4}{6}$$

Multiply 7 and 4 to get 28.

$$968-\frac{28}{6}$$

Reduce the fraction \frac{28}{6} to lowest terms by extracting and canceling out 2.

$$968-\frac{14}{3}$$

Convert 968 to fraction \frac{2904}{3}.

$$\frac{2904}{3}-\frac{14}{3}$$

Since \frac{2904}{3} and \frac{14}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2904-14}{3}$$

Subtract 14 from 2904 to get 2890.

$$\frac{2890}{3}$$

Factor

$$\frac{2 \cdot 5 \cdot 17 ^ {2}}{3} = 963\frac{1}{3} = 963.3333333333334$$