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2\left(28x^{2}-3x\right)
Factor out 2.
x\left(28x-3\right)
Consider 28x^{2}-3x. Factor out x.
2x\left(28x-3\right)
Rewrite the complete factored expression.
56x^{2}-6x=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}}}{2\times 56}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-6\right)±6}{2\times 56}
Take the square root of \left(-6\right)^{2}.
x=\frac{6±6}{2\times 56}
The opposite of -6 is 6.
x=\frac{6±6}{112}
Multiply 2 times 56.
x=\frac{12}{112}
Now solve the equation x=\frac{6±6}{112} when ± is plus. Add 6 to 6.
x=\frac{3}{28}
Reduce the fraction \frac{12}{112} to lowest terms by extracting and canceling out 4.
x=\frac{0}{112}
Now solve the equation x=\frac{6±6}{112} when ± is minus. Subtract 6 from 6.
x=0
Divide 0 by 112.
56x^{2}-6x=56\left(x-\frac{3}{28}\right)x
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{3}{28} for x_{1} and 0 for x_{2}.
56x^{2}-6x=56\times \frac{28x-3}{28}x
Subtract \frac{3}{28} from x by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.
56x^{2}-6x=2\left(28x-3\right)x
Cancel out 28, the greatest common factor in 56 and 28.