Solve 56div6+(47-17)div5-13

$$56 \div 6+(47-17) \div 5-13$$

Evaluate

$$\frac{7}{3}\approx 2.333333333$$

Solution Steps

Reduce the fraction \frac{56}{6} to lowest terms by extracting and canceling out 2.

$$\frac{28}{3}+\frac{47-17}{5}-13$$

Subtract 17 from 47 to get 30.

$$\frac{28}{3}+\frac{30}{5}-13$$

Divide 30 by 5 to get 6.

$$\frac{28}{3}+6-13$$

Convert 6 to fraction \frac{18}{3}.

$$\frac{28}{3}+\frac{18}{3}-13$$

Since \frac{28}{3} and \frac{18}{3} have the same denominator, add them by adding their numerators.

$$\frac{28+18}{3}-13$$

Add 28 and 18 to get 46.

$$\frac{46}{3}-13$$

Convert 13 to fraction \frac{39}{3}.

$$\frac{46}{3}-\frac{39}{3}$$

Since \frac{46}{3} and \frac{39}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{46-39}{3}$$

Subtract 39 from 46 to get 7.

$$\frac{7}{3}$$

Factor

$$\frac{7}{3} = 2\frac{1}{3} = 2.3333333333333335$$