Solve for x
x=\frac{2z}{11}+\frac{47y}{55}
Solve for y
y=\frac{55x-10z}{47}
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55x=10z+47y
Add 47y to both sides.
55x=47y+10z
The equation is in standard form.
\frac{55x}{55}=\frac{47y+10z}{55}
Divide both sides by 55.
x=\frac{47y+10z}{55}
Dividing by 55 undoes the multiplication by 55.
x=\frac{2z}{11}+\frac{47y}{55}
Divide 10z+47y by 55.
-47y=10z-55x
Subtract 55x from both sides.
\frac{-47y}{-47}=\frac{10z-55x}{-47}
Divide both sides by -47.
y=\frac{10z-55x}{-47}
Dividing by -47 undoes the multiplication by -47.
y=\frac{55x-10z}{47}
Divide 10z-55x by -47.
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