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\frac{5555555555555555}{11111111111225562556543}=x^{2}
Multiply x and x to get x^{2}.
x^{2}=\frac{5555555555555555}{11111111111225562556543}
Swap sides so that all variable terms are on the left hand side.
x=\frac{\sqrt{61728395062364230252399382652465246365}}{11111111111225562556543} x=-\frac{\sqrt{61728395062364230252399382652465246365}}{11111111111225562556543}
Take the square root of both sides of the equation.
\frac{5555555555555555}{11111111111225562556543}=x^{2}
Multiply x and x to get x^{2}.
x^{2}=\frac{5555555555555555}{11111111111225562556543}
Swap sides so that all variable terms are on the left hand side.
x^{2}-\frac{5555555555555555}{11111111111225562556543}=0
Subtract \frac{5555555555555555}{11111111111225562556543} from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{5555555555555555}{11111111111225562556543}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{5555555555555555}{11111111111225562556543} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{5555555555555555}{11111111111225562556543}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{\frac{22222222222222220}{11111111111225562556543}}}{2}
Multiply -4 times -\frac{5555555555555555}{11111111111225562556543}.
x=\frac{0±\frac{2\sqrt{61728395062364230252399382652465246365}}{11111111111225562556543}}{2}
Take the square root of \frac{22222222222222220}{11111111111225562556543}.
x=\frac{\sqrt{61728395062364230252399382652465246365}}{11111111111225562556543}
Now solve the equation x=\frac{0±\frac{2\sqrt{61728395062364230252399382652465246365}}{11111111111225562556543}}{2} when ± is plus.
x=-\frac{\sqrt{61728395062364230252399382652465246365}}{11111111111225562556543}
Now solve the equation x=\frac{0±\frac{2\sqrt{61728395062364230252399382652465246365}}{11111111111225562556543}}{2} when ± is minus.
x=\frac{\sqrt{61728395062364230252399382652465246365}}{11111111111225562556543} x=-\frac{\sqrt{61728395062364230252399382652465246365}}{11111111111225562556543}
The equation is now solved.