Solve 55040divlceil16^2*1.72rceil

$$55040 \div \lceil { 16 }^{ 2 } \times 1.72 \rceil$$

Evaluate

$$\frac{55040}{441}\approx 124.807256236$$

Solution Steps

Calculate 16 to the power of 2 and get 256.

$$\frac{55040}{\lceil 256\times 1.72\rceil }$$

Multiply 256 and 1.72 to get 440.32.

$$\frac{55040}{\lceil 440.32\rceil }$$

The ceiling of a real number a is the smallest integer number greater than or equal to a. The ceiling of 440.32 is 441.

$$\frac{55040}{441}$$

Factor

$$\frac{5 \cdot 43 \cdot 2 ^ {8}}{3 ^ {2} \cdot 7 ^ {2}} = 124\frac{356}{441} = 124.80725623582767$$