Solve 545ngeq-252+425n

$$545 n \geq - 252 + 425 n$$

Solve for n

$$n\geq -\frac{21}{10}$$

Solution Steps

Subtract 425n from both sides.

$$545n-425n\geq -252$$

Combine 545n and -425n to get 120n.

$$120n\geq -252$$

Divide both sides by 120. Since 120 is positive, the inequality direction remains the same.

$$n\geq \frac{-252}{120}$$

Reduce the fraction \frac{-252}{120} to lowest terms by extracting and canceling out 12.

$$n\geq -\frac{21}{10}$$