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2\left(27x^{2}+x^{2}y^{6}\right)
Factor out 2.
x^{2}\left(27+y^{6}\right)
Consider 27x^{2}+x^{2}y^{6}. Factor out x^{2}.
\left(y^{2}+3\right)\left(y^{4}-3y^{2}+9\right)
Consider 27+y^{6}. Rewrite 27+y^{6} as \left(y^{2}\right)^{3}+3^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
2x^{2}\left(y^{2}+3\right)\left(y^{4}-3y^{2}+9\right)
Rewrite the complete factored expression. The following polynomials are not factored since they do not have any rational roots: y^{2}+3,y^{4}-3y^{2}+9.