Factor
\left(8z-5\right)\left(64z^{2}+40z+25\right)
Evaluate
512z^{3}-125
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\left(8z-5\right)\left(64z^{2}+40z+25\right)
Rewrite 512z^{3}-125 as \left(8z\right)^{3}-5^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial 64z^{2}+40z+25 is not factored since it does not have any rational roots.
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