Solve 51x+81/43=79x

$$51 x + \frac { 81 } { 43 } = 79 x$$

Solve for x

$$x=\frac{81}{1204}\approx 0.067275748$$

Steps for Solving Linear Equation

Subtract 79x from both sides.

$$51x+\frac{81}{43}-79x=0$$

Combine 51x and -79x to get -28x.

$$-28x+\frac{81}{43}=0$$

Subtract \frac{81}{43} from both sides. Anything subtracted from zero gives its negation.

$$-28x=-\frac{81}{43}$$

Divide both sides by -28.

$$x=\frac{-\frac{81}{43}}{-28}$$

Express \frac{-\frac{81}{43}}{-28} as a single fraction.

$$x=\frac{-81}{43\left(-28\right)}$$

Multiply 43 and -28 to get -1204.

$$x=\frac{-81}{-1204}$$

Fraction \frac{-81}{-1204} can be simplified to \frac{81}{1204} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{81}{1204}$$