Solve 50000(1+x%)(1+x%+1%)-50000

$$50000(1+x \% )(1+x \% +1 \% )-50000$$

Evaluate

$$5\left(x^{2}+201x+100\right)$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{100}{100}.

$$50000\left(\frac{100}{100}+\frac{x}{100}\right)\left(1+\frac{x}{100}+\frac{1}{100}\right)-50000$$

Since \frac{100}{100} and \frac{x}{100} have the same denominator, add them by adding their numerators.

$$50000\times \frac{100+x}{100}\left(1+\frac{x}{100}+\frac{1}{100}\right)-50000$$

Convert 1 to fraction \frac{100}{100}.

$$50000\times \frac{100+x}{100}\left(\frac{100}{100}+\frac{x}{100}+\frac{1}{100}\right)-50000$$

Since \frac{100}{100} and \frac{1}{100} have the same denominator, add them by adding their numerators.

$$50000\times \frac{100+x}{100}\left(\frac{100+1}{100}+\frac{x}{100}\right)-50000$$

Add 100 and 1 to get 101.

$$50000\times \frac{100+x}{100}\left(\frac{101}{100}+\frac{x}{100}\right)-50000$$

Since \frac{101}{100} and \frac{x}{100} have the same denominator, add them by adding their numerators.

$$50000\times \frac{100+x}{100}\times \frac{101+x}{100}-50000$$

Cancel out 100, the greatest common factor in 50000 and 100.

$$500\left(100+x\right)\times \frac{101+x}{100}-50000$$

Express 500\left(100+x\right)\times \frac{101+x}{100} as a single fraction.

$$\frac{500\left(100+x\right)\left(101+x\right)}{100}-50000$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 50000 times \frac{100}{100}.

$$\frac{500\left(100+x\right)\left(101+x\right)}{100}-\frac{50000\times 100}{100}$$

Since \frac{500\left(100+x\right)\left(101+x\right)}{100} and \frac{50000\times 100}{100} have the same denominator, subtract them by subtracting their numerators.

$$\frac{500\left(100+x\right)\left(101+x\right)-50000\times 100}{100}$$

Do the multiplications in 500\left(100+x\right)\left(101+x\right)-50000\times 100.

$$\frac{5050000+50000x+50500x+500x^{2}-5000000}{100}$$

Combine like terms in 5050000+50000x+50500x+500x^{2}-5000000.

$$\frac{50000+100500x+500x^{2}}{100}$$

Expand

$$5x^{2}+1005x+500$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{100}{100}.

$$50000\left(\frac{100}{100}+\frac{x}{100}\right)\left(1+\frac{x}{100}+\frac{1}{100}\right)-50000$$

Since \frac{100}{100} and \frac{x}{100} have the same denominator, add them by adding their numerators.

$$50000\times \frac{100+x}{100}\left(1+\frac{x}{100}+\frac{1}{100}\right)-50000$$

Convert 1 to fraction \frac{100}{100}.

$$50000\times \frac{100+x}{100}\left(\frac{100}{100}+\frac{x}{100}+\frac{1}{100}\right)-50000$$

Since \frac{100}{100} and \frac{1}{100} have the same denominator, add them by adding their numerators.

$$50000\times \frac{100+x}{100}\left(\frac{100+1}{100}+\frac{x}{100}\right)-50000$$

Add 100 and 1 to get 101.

$$50000\times \frac{100+x}{100}\left(\frac{101}{100}+\frac{x}{100}\right)-50000$$

Since \frac{101}{100} and \frac{x}{100} have the same denominator, add them by adding their numerators.

$$50000\times \frac{100+x}{100}\times \frac{101+x}{100}-50000$$

Cancel out 100, the greatest common factor in 50000 and 100.

$$500\left(100+x\right)\times \frac{101+x}{100}-50000$$

Express 500\left(100+x\right)\times \frac{101+x}{100} as a single fraction.

$$\frac{500\left(100+x\right)\left(101+x\right)}{100}-50000$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 50000 times \frac{100}{100}.

$$\frac{500\left(100+x\right)\left(101+x\right)}{100}-\frac{50000\times 100}{100}$$

Since \frac{500\left(100+x\right)\left(101+x\right)}{100} and \frac{50000\times 100}{100} have the same denominator, subtract them by subtracting their numerators.

$$\frac{500\left(100+x\right)\left(101+x\right)-50000\times 100}{100}$$

Do the multiplications in 500\left(100+x\right)\left(101+x\right)-50000\times 100.

$$\frac{5050000+50000x+50500x+500x^{2}-5000000}{100}$$

Combine like terms in 5050000+50000x+50500x+500x^{2}-5000000.

$$\frac{50000+100500x+500x^{2}}{100}$$