Solve 5000(1+n)^2=5350

$$5000 ( 1 + n ) ^ { 2 } = 5350$$

Solve for n

$$n=\frac{\sqrt{107}}{10}-1\approx 0.034408043$$

$$n=-\frac{\sqrt{107}}{10}-1\approx -2.034408043$$

Steps by Finding Square Root

Divide both sides by 5000.

$$\frac{5000\left(n+1\right)^{2}}{5000}=\frac{5350}{5000}$$

Dividing by 5000 undoes the multiplication by 5000.

$$\left(n+1\right)^{2}=\frac{5350}{5000}$$

Reduce the fraction \frac{5350}{5000} to lowest terms by extracting and canceling out 50.

$$\left(n+1\right)^{2}=\frac{107}{100}$$

Take the square root of both sides of the equation.

$$n+1=\frac{\sqrt{107}}{10} n+1=-\frac{\sqrt{107}}{10}$$

Subtract 1 from both sides of the equation.

$$n+1-1=\frac{\sqrt{107}}{10}-1 n+1-1=-\frac{\sqrt{107}}{10}-1$$

Subtracting 1 from itself leaves 0.

$$n=\frac{\sqrt{107}}{10}-1 n=-\frac{\sqrt{107}}{10}-1$$