Solve 50x+40y=50x+1x+40*085y

$$50 x + 40 y = 50 x + 1 x + 40 \times 085 y$$

Solve for x

$$x=40y$$

Steps for Solving Linear Equation

Combine 50x and 1x to get 51x.

$$50x+40y=51x+40\times 0\times 85y$$

Multiply 40 and 0 to get 0.

$$50x+40y=51x+0\times 85y$$

Multiply 0 and 85 to get 0.

$$50x+40y=51x+0y$$

Anything times zero gives zero.

$$50x+40y=51x+0$$

Anything plus zero gives itself.

$$50x+40y=51x$$

Subtract 51x from both sides.

$$50x+40y-51x=0$$

Combine 50x and -51x to get -x.

$$-x+40y=0$$

Subtract 40y from both sides. Anything subtracted from zero gives its negation.

$$-x=-40y$$

Divide both sides by -1.

$$\frac{-x}{-1}=-\frac{40y}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=-\frac{40y}{-1}$$

Divide -40y by -1.

$$x=40y$$

Solve for y

$$y=\frac{x}{40}$$

Steps for Solving Linear Equation

Combine 50x and 1x to get 51x.

$$50x+40y=51x+40\times 0\times 85y$$

Multiply 40 and 0 to get 0.

$$50x+40y=51x+0\times 85y$$

Multiply 0 and 85 to get 0.

$$50x+40y=51x+0y$$

Anything times zero gives zero.

$$50x+40y=51x+0$$

Anything plus zero gives itself.

$$50x+40y=51x$$

Subtract 50x from both sides.

$$40y=51x-50x$$

Combine 51x and -50x to get x.

$$40y=x$$

Divide both sides by 40.

$$\frac{40y}{40}=\frac{x}{40}$$

Dividing by 40 undoes the multiplication by 40.

$$y=\frac{x}{40}$$