Solve 50-{10div14-[3+(-6+3)-(12-1)]-4}

$$50 - \{ 10 \div 14 - [ 3 + ( - 6 + 3 ) - ( 12 - 1 ) ] - 4 \}$$

Evaluate

$$\frac{296}{7}\approx 42.285714286$$

Solution Steps

Reduce the fraction \frac{10}{14} to lowest terms by extracting and canceling out 2.

$$50-\left(\frac{5}{7}-\left(3-6+3-\left(12-1\right)\right)-4\right)$$

Subtract 6 from 3 to get -3.

$$50-\left(\frac{5}{7}-\left(-3+3-\left(12-1\right)\right)-4\right)$$

Add -3 and 3 to get 0.

$$50-\left(\frac{5}{7}-\left(0-\left(12-1\right)\right)-4\right)$$

Subtract 1 from 12 to get 11.

$$50-\left(\frac{5}{7}-\left(0-11\right)-4\right)$$

Subtract 11 from 0 to get -11.

$$50-\left(\frac{5}{7}-\left(-11\right)-4\right)$$

The opposite of -11 is 11.

$$50-\left(\frac{5}{7}+11-4\right)$$

Convert 11 to fraction \frac{77}{7}.

$$50-\left(\frac{5}{7}+\frac{77}{7}-4\right)$$

Since \frac{5}{7} and \frac{77}{7} have the same denominator, add them by adding their numerators.

$$50-\left(\frac{5+77}{7}-4\right)$$

Add 5 and 77 to get 82.

$$50-\left(\frac{82}{7}-4\right)$$

Convert 4 to fraction \frac{28}{7}.

$$50-\left(\frac{82}{7}-\frac{28}{7}\right)$$

Since \frac{82}{7} and \frac{28}{7} have the same denominator, subtract them by subtracting their numerators.

$$50-\frac{82-28}{7}$$

Subtract 28 from 82 to get 54.

$$50-\frac{54}{7}$$

Convert 50 to fraction \frac{350}{7}.

$$\frac{350}{7}-\frac{54}{7}$$

Since \frac{350}{7} and \frac{54}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{350-54}{7}$$

Subtract 54 from 350 to get 296.

$$\frac{296}{7}$$

Factor

$$\frac{2 ^ {3} \cdot 37}{7} = 42\frac{2}{7} = 42.285714285714285$$