Solve 50left(1+xright)^2=72/50

$$50 { \left(1+x \right) }^{ 2 } = \frac{ 72 }{ 50 }$$

Solve for x

$$x=\frac{3\sqrt{2}}{25}-1\approx -0.830294373$$

$$x=-\frac{3\sqrt{2}}{25}-1\approx -1.169705627$$

Steps by Finding Square Root

Divide both sides by 50.

$$\frac{50\left(x+1\right)^{2}}{50}=\frac{\frac{36}{25}}{50}$$

Dividing by 50 undoes the multiplication by 50.

$$\left(x+1\right)^{2}=\frac{\frac{36}{25}}{50}$$

Divide \frac{36}{25} by 50.

$$\left(x+1\right)^{2}=\frac{18}{625}$$

Take the square root of both sides of the equation.

$$x+1=\frac{3\sqrt{2}}{25} x+1=-\frac{3\sqrt{2}}{25}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{3\sqrt{2}}{25}-1 x+1-1=-\frac{3\sqrt{2}}{25}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{3\sqrt{2}}{25}-1 x=-\frac{3\sqrt{2}}{25}-1$$