Solve 50*(0.85+j0.385)*(220/10.5)^2

$$50 \times ( 0.85 + j 0.385 ) \times ( \frac { 220 } { 10.5 } ) ^ { 2 }$$

Evaluate

$$\frac{532400j_{0}}{63}+\frac{8228000}{441}$$

Solution Steps

Expand \frac{220}{10.5} by multiplying both numerator and the denominator by 10.

$$50\left(0.85+j_{0}\times 0.385\right)\times \left(\frac{2200}{105}\right)^{2}$$

Reduce the fraction \frac{2200}{105} to lowest terms by extracting and canceling out 5.

$$50\left(0.85+j_{0}\times 0.385\right)\times \left(\frac{440}{21}\right)^{2}$$

Calculate \frac{440}{21} to the power of 2 and get \frac{193600}{441}.

$$50\left(0.85+j_{0}\times 0.385\right)\times \frac{193600}{441}$$

Multiply 50 and \frac{193600}{441} to get \frac{9680000}{441}.

$$\frac{9680000}{441}\left(0.85+j_{0}\times 0.385\right)$$

Use the distributive property to multiply \frac{9680000}{441} by 0.85+j_{0}\times 0.385.

$$\frac{8228000}{441}+\frac{9680000}{441}j_{0}\times 0.385$$

Multiply \frac{9680000}{441} and 0.385 to get \frac{532400}{63}.

$$\frac{8228000}{441}+\frac{532400}{63}j_{0}$$

Expand

$$\frac{532400j_{0}}{63}+\frac{8228000}{441}$$

Solution Steps

Expand \frac{220}{10.5} by multiplying both numerator and the denominator by 10.

$$50\left(0.85+j_{0}\times 0.385\right)\times \left(\frac{2200}{105}\right)^{2}$$

Reduce the fraction \frac{2200}{105} to lowest terms by extracting and canceling out 5.

$$50\left(0.85+j_{0}\times 0.385\right)\times \left(\frac{440}{21}\right)^{2}$$

Calculate \frac{440}{21} to the power of 2 and get \frac{193600}{441}.

$$50\left(0.85+j_{0}\times 0.385\right)\times \frac{193600}{441}$$

Multiply 50 and \frac{193600}{441} to get \frac{9680000}{441}.

$$\frac{9680000}{441}\left(0.85+j_{0}\times 0.385\right)$$

Use the distributive property to multiply \frac{9680000}{441} by 0.85+j_{0}\times 0.385.

$$\frac{8228000}{441}+\frac{9680000}{441}j_{0}\times 0.385$$

Multiply \frac{9680000}{441} and 0.385 to get \frac{532400}{63}.

$$\frac{8228000}{441}+\frac{532400}{63}j_{0}$$