Solve 50=sqrt{80^2-x}

$$50 = \sqrt{ { 80 }^{ 2 } -x }$$

Solve for x

$$x=3900$$

Steps for Solving Radical Equations

Calculate 80 to the power of 2 and get 6400.

$$50=\sqrt{6400-x}$$

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{6400-x}=50$$

Square both sides of the equation.

$$-x+6400=2500$$

Subtract 6400 from both sides of the equation.

$$-x+6400-6400=2500-6400$$

Subtracting 6400 from itself leaves 0.

$$-x=2500-6400$$

Subtract 6400 from 2500.

$$-x=-3900$$

Divide both sides by -1.

$$\frac{-x}{-1}=-\frac{3900}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=-\frac{3900}{-1}$$

Divide -3900 by -1.

$$x=3900$$