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5.76x^{2}+2.86x-1.35=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-2.86±\sqrt{2.86^{2}-4\times 5.76\left(-1.35\right)}}{2\times 5.76}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5.76 for a, 2.86 for b, and -1.35 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-2.86±\sqrt{8.1796-4\times 5.76\left(-1.35\right)}}{2\times 5.76}
Square 2.86 by squaring both the numerator and the denominator of the fraction.
x=\frac{-2.86±\sqrt{8.1796-23.04\left(-1.35\right)}}{2\times 5.76}
Multiply -4 times 5.76.
x=\frac{-2.86±\sqrt{8.1796+31.104}}{2\times 5.76}
Multiply -23.04 times -1.35 by multiplying numerator times numerator and denominator times denominator. Then reduce the fraction to lowest terms if possible.
x=\frac{-2.86±\sqrt{39.2836}}{2\times 5.76}
Add 8.1796 to 31.104 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
x=\frac{-2.86±\frac{\sqrt{98209}}{50}}{2\times 5.76}
Take the square root of 39.2836.
x=\frac{-2.86±\frac{\sqrt{98209}}{50}}{11.52}
Multiply 2 times 5.76.
x=\frac{\sqrt{98209}-143}{11.52\times 50}
Now solve the equation x=\frac{-2.86±\frac{\sqrt{98209}}{50}}{11.52} when ± is plus. Add -2.86 to \frac{\sqrt{98209}}{50}.
x=\frac{\sqrt{98209}-143}{576}
Divide \frac{-143+\sqrt{98209}}{50} by 11.52 by multiplying \frac{-143+\sqrt{98209}}{50} by the reciprocal of 11.52.
x=\frac{-\sqrt{98209}-143}{11.52\times 50}
Now solve the equation x=\frac{-2.86±\frac{\sqrt{98209}}{50}}{11.52} when ± is minus. Subtract \frac{\sqrt{98209}}{50} from -2.86.
x=\frac{-\sqrt{98209}-143}{576}
Divide \frac{-143-\sqrt{98209}}{50} by 11.52 by multiplying \frac{-143-\sqrt{98209}}{50} by the reciprocal of 11.52.
x=\frac{\sqrt{98209}-143}{576} x=\frac{-\sqrt{98209}-143}{576}
The equation is now solved.
5.76x^{2}+2.86x-1.35=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
5.76x^{2}+2.86x-1.35-\left(-1.35\right)=-\left(-1.35\right)
Add 1.35 to both sides of the equation.
5.76x^{2}+2.86x=-\left(-1.35\right)
Subtracting -1.35 from itself leaves 0.
5.76x^{2}+2.86x=1.35
Subtract -1.35 from 0.
\frac{5.76x^{2}+2.86x}{5.76}=\frac{1.35}{5.76}
Divide both sides of the equation by 5.76, which is the same as multiplying both sides by the reciprocal of the fraction.
x^{2}+\frac{2.86}{5.76}x=\frac{1.35}{5.76}
Dividing by 5.76 undoes the multiplication by 5.76.
x^{2}+\frac{143}{288}x=\frac{1.35}{5.76}
Divide 2.86 by 5.76 by multiplying 2.86 by the reciprocal of 5.76.
x^{2}+\frac{143}{288}x=0.234375
Divide 1.35 by 5.76 by multiplying 1.35 by the reciprocal of 5.76.
x^{2}+\frac{143}{288}x+\frac{143}{576}^{2}=0.234375+\frac{143}{576}^{2}
Divide \frac{143}{288}, the coefficient of the x term, by 2 to get \frac{143}{576}. Then add the square of \frac{143}{576} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+\frac{143}{288}x+\frac{20449}{331776}=0.234375+\frac{20449}{331776}
Square \frac{143}{576} by squaring both the numerator and the denominator of the fraction.
x^{2}+\frac{143}{288}x+\frac{20449}{331776}=\frac{98209}{331776}
Add 0.234375 to \frac{20449}{331776} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x+\frac{143}{576}\right)^{2}=\frac{98209}{331776}
Factor x^{2}+\frac{143}{288}x+\frac{20449}{331776}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{143}{576}\right)^{2}}=\sqrt{\frac{98209}{331776}}
Take the square root of both sides of the equation.
x+\frac{143}{576}=\frac{\sqrt{98209}}{576} x+\frac{143}{576}=-\frac{\sqrt{98209}}{576}
Simplify.
x=\frac{\sqrt{98209}-143}{576} x=\frac{-\sqrt{98209}-143}{576}
Subtract \frac{143}{576} from both sides of the equation.