Solve 5(x+3)+x=4(x+3)+3

$$5(x+3)+x=4(x+3)+3$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5 by x+3.

$$5x+15+x=4\left(x+3\right)+3$$

Combine 5x and x to get 6x.

$$6x+15=4\left(x+3\right)+3$$

Use the distributive property to multiply 4 by x+3.

$$6x+15=4x+12+3$$

Add 12 and 3 to get 15.

$$6x+15=4x+15$$

Subtract 4x from both sides.

$$6x+15-4x=15$$

Combine 6x and -4x to get 2x.

$$2x+15=15$$

Subtract 15 from both sides.

$$2x=15-15$$

Subtract 15 from 15 to get 0.

$$2x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 2 is not equal to 0, x must be equal to 0.

$$x=0$$