Solve 5(3x-2)-3>3(7x+6)+11

$$5(3x-2)-3 > 3(7x+6)+11$$

Solve for x

$$x<-7$$

Solution Steps

Use the distributive property to multiply 5 by 3x-2.

$$15x-10-3>3\left(7x+6\right)+11$$

Subtract 3 from -10 to get -13.

$$15x-13>3\left(7x+6\right)+11$$

Use the distributive property to multiply 3 by 7x+6.

$$15x-13>21x+18+11$$

Add 18 and 11 to get 29.

$$15x-13>21x+29$$

Subtract 21x from both sides.

$$15x-13-21x>29$$

Combine 15x and -21x to get -6x.

$$-6x-13>29$$

Add 13 to both sides.

$$-6x>29+13$$

Add 29 and 13 to get 42.

$$-6x>42$$

Divide both sides by -6. Since -6 is negative, the inequality direction is changed.

$$x<\frac{42}{-6}$$

Divide 42 by -6 to get -7.

$$x<-7$$