Solve 5(2x-4(3x+1))=-10x+20

$$5(2x-4(3x+1))=-10x+20$$

Solve for x

$$x=-1$$

Steps for Solving Linear Equation

Use the distributive property to multiply -4 by 3x+1.

$$5\left(2x-12x-4\right)=-10x+20$$

Combine 2x and -12x to get -10x.

$$5\left(-10x-4\right)=-10x+20$$

Use the distributive property to multiply 5 by -10x-4.

$$-50x-20=-10x+20$$

Add 10x to both sides.

$$-50x-20+10x=20$$

Combine -50x and 10x to get -40x.

$$-40x-20=20$$

Add 20 to both sides.

$$-40x=20+20$$

Add 20 and 20 to get 40.

$$-40x=40$$

Divide both sides by -40.

$$x=\frac{40}{-40}$$

Divide 40 by -40 to get -1.

$$x=-1$$