Solve 5=8+x/1+8

$$5= \frac{ 8+x }{ 1+8 }$$

Solve for x

$$x=37$$

Steps for Solving Linear Equation

Add 1 and 8 to get 9.

$$5=\frac{8+x}{9}$$

Divide each term of 8+x by 9 to get \frac{8}{9}+\frac{1}{9}x.

$$5=\frac{8}{9}+\frac{1}{9}x$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{8}{9}+\frac{1}{9}x=5$$

Subtract \frac{8}{9} from both sides.

$$\frac{1}{9}x=5-\frac{8}{9}$$

Convert 5 to fraction \frac{45}{9}.

$$\frac{1}{9}x=\frac{45}{9}-\frac{8}{9}$$

Since \frac{45}{9} and \frac{8}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{9}x=\frac{45-8}{9}$$

Subtract 8 from 45 to get 37.

$$\frac{1}{9}x=\frac{37}{9}$$

Multiply both sides by 9, the reciprocal of \frac{1}{9}.

$$x=\frac{37}{9}\times 9$$

Cancel out 9 and 9.

$$x=37$$